Code for validating xml against xsd in java
This article shows five ways of how to configure different Java APIs (including DOM, SAX, dom4j and XOM) using JAXP 1.3 for checking and validating XML with DTD and Schema(s).To report errors, it is necessary to provide an Error Handler to the underlying implementation.To done this, first we need to have this “xsd-gen-VERSION-jar-with-dependencies.jar” jar file. In this example I am using the xsd-gen-0.2.0version of the jar file. An any Type type does not constrain its content in any way. See here Type If you add this line into your schema, top level, then your XML is valid.
XML schema defines the elements that form an XML document. Here is the sample XML file: In the jar file, the Xsd Gen constructors are default package access specifies, so you can not create the instance of this class outside of the package, you need to modify the source code of Xsd Gen constructors to public access specifies to create the instance of this class. You will find the source code of the Xsd Gen class in the following location: " Hello, I am trying to validate an xml file against an xsd in java 1.4.
The code below works flawlessly in java 1.5 but in 1.4 I can't set Attributes.
Is there any way from which I can configure within XML SPY so that a user can give anything (both elements and text). Hopefully someone else can explain why xsd:any Type resolves to xsd:string. - madhav ps: I din't know I was competing with Dan. [ January 22, 2003: Message edited by: Madhav Lakkapragada ] To my understanding, any Type could contain any mixed text and elements.